What is the solution for v^{''}-1v=2e^{4x} ?

The solution for v^{''}-1v=2e^{4x} is v(x)=c_{1}e^x+c_{2}e^{-x}+2/15 e^{4x}

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v^{''}-1v=2e^{4x}

v^{^{''}} - 1 v = 2 e^{4 x}

v (x) = c_{1} e^{x} + c_{2} e^{- x} + \frac{2}{15} e^{4 x}

Solution steps

v^{''} (x) - 1 v (x) = 2 e^{4 x}

Solve linear ODE:

v (x) = c_{1} e^{x} + c_{2} e^{- x} + \frac{2}{15} e^{4 x}

v (x) = c_{1} e^{x} + c_{2} e^{- x} + \frac{2}{15} e^{4 x}

What is the solution for v^{''}-1v=2e^{4x} ?
The solution for v^{''}-1v=2e^{4x} is v(x)=c_{1}e^x+c_{2}e^{-x}+2/15 e^{4x}