y^{''}-2y^'=x^2-1

Lösung

y^{^{''}} - 2 y^{^{'}} = x^{2} - 1

y = c_{1} e^{2 x} + c_{2} - \frac{x ^{3}}{6} - \frac{x ^{2}}{4} + \frac{x}{4}

Schritte zur Lösung

y^{''} (x) - 2 y^{'} (x) = x^{2} - 1

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} - \frac{x ^{3}}{6} - \frac{x ^{2}}{4} + \frac{x}{4}

y = c_{1} e^{2 x} + c_{2} - \frac{x ^{3}}{6} - \frac{x ^{2}}{4} + \frac{x}{4}