Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}+y^'-12y=xe^{2x}x^{''}-2x^'-x=e^{2t}y^{''}-y=e^xcos(x),y(0)=0,y^'(0)=0y^{''}-10y^'+25y=t^{-6}e^{5t}y^{''}-y^'-2y=xe^{4x}
Frequently Asked Questions (FAQ)
What is the solution for y^{''}-4y=e^{5x} ?
The solution for y^{''}-4y=e^{5x} is y=c_{1}e^{2x}+c_{2}e^{-2x}+1/21 e^{5x}