Solution
Solution
Solution steps
Solve linear ODE:
Popular Examples
y^{''}-2y^'+2y=e-t,y(0)=0,y^'(0)=1y^{''}-2y-3y=-3xe^{-x}y^{''}+6y^'+8y=t\H(t-3)1/2 y^{''}+2y=4tan(2t)-1/3 e^{2t}x^{''}+16x=102e^{-2t}cos(4t)
Frequently Asked Questions (FAQ)
What is the solution for y^{''}+3y+2=0,y(2)=-1,y^'(0)=0 ?
The solution for y^{''}+3y+2=0,y(2)=-1,y^'(0)=0 is y=-(cos(sqrt(3)t))/(3cos(2sqrt(3)))-2/3