What is the solution for y^{''}+2y^'+y=1,y(0)=2 ?

The solution for y^{''}+2y^'+y=1,y(0)=2 is y=e^{-t}+c_{2}e^{-t}t+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+2y^'+y=1,y(0)=2

y^{^{''}} + 2 y^{^{'}} + y = 1, y (0) = 2

y = e^{- t} + c_{2} e^{- t} t + 1

Solution steps

y^{''} (t) + 2 y^{'} (t) + y = 1

Solve linear ODE:

y = e^{- t} + c_{2} e^{- t} t + 1

y = e^{- t} + c_{2} e^{- t} t + 1

What is the solution for y^{''}+2y^'+y=1,y(0)=2 ?
The solution for y^{''}+2y^'+y=1,y(0)=2 is y=e^{-t}+c_{2}e^{-t}t+1