What is the solution for y^{''}-y^'-6y=69cos(3x) ?

The solution for y^{''}-y^'-6y=69cos(3x) is y=c_{1}e^{3x}+c_{2}e^{-2x}-23/26 sin(3x)-115/26 cos(3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-y^'-6y=69cos(3x)

y^{^{''}} - y^{^{'}} - 6 y = 69 cos (3 x)

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} - \frac{23}{26} sin (3 x) - \frac{115}{26} cos (3 x)

Solution steps

y^{''} (x) - y^{'} (x) - 6 y = 69 cos (3 x)

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} - \frac{23}{26} sin (3 x) - \frac{115}{26} cos (3 x)

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} - \frac{23}{26} sin (3 x) - \frac{115}{26} cos (3 x)

What is the solution for y^{''}-y^'-6y=69cos(3x) ?
The solution for y^{''}-y^'-6y=69cos(3x) is y=c_{1}e^{3x}+c_{2}e^{-2x}-23/26 sin(3x)-115/26 cos(3x)