What is the solution for y^{''}+6y^'+8y=-3e^{-t} ?

The solution for y^{''}+6y^'+8y=-3e^{-t} is y=c_{1}e^{-2t}+c_{2}e^{-4t}-e^{-t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+6y^'+8y=-3e^{-t}

y^{^{''}} + 6 y^{^{'}} + 8 y = - 3 e^{- t}

y = c_{1} e^{- 2 t} + c_{2} e^{- 4 t} - e^{- t}

Solution steps

y^{''} (t) + 6 y^{'} (t) + 8 y = - 3 e^{- t}

Solve linear ODE:

y = c_{1} e^{- 2 t} + c_{2} e^{- 4 t} - e^{- t}

y = c_{1} e^{- 2 t} + c_{2} e^{- 4 t} - e^{- t}

What is the solution for y^{''}+6y^'+8y=-3e^{-t} ?
The solution for y^{''}+6y^'+8y=-3e^{-t} is y=c_{1}e^{-2t}+c_{2}e^{-4t}-e^{-t}