What is the solution for y^{''}+4y=4t^2-4t+10 ?

The solution for y^{''}+4y=4t^2-4t+10 is y=c_{1}cos(2t)+c_{2}sin(2t)+t^2-t+2

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y^{''}+4y=4t^2-4t+10

y^{^{''}} + 4 y = 4 t^{2} - 4 t + 10

y = c_{1} cos (2 t) + c_{2} sin (2 t) + t^{2} - t + 2

Solution steps

y^{''} (t) + 4 y = 4 t^{2} - 4 t + 10

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t) + t^{2} - t + 2

y = c_{1} cos (2 t) + c_{2} sin (2 t) + t^{2} - t + 2

What is the solution for y^{''}+4y=4t^2-4t+10 ?
The solution for y^{''}+4y=4t^2-4t+10 is y=c_{1}cos(2t)+c_{2}sin(2t)+t^2-t+2