What is the solution for y^{''}+3y+2=0 ?

The solution for y^{''}+3y+2=0 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)-2/3

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y^{''}+3y+2=0

y^{^{''}} + 3 y + 2 = 0

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{2}{3}

Solution steps

y^{''} (t) + 3 y + 2 = 0

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{2}{3}

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{2}{3}

What is the solution for y^{''}+3y+2=0 ?
The solution for y^{''}+3y+2=0 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)-2/3