What is the solution for y^{''}+5y^'+6y=-5-e^x ?

The solution for y^{''}+5y^'+6y=-5-e^x is y=c_{1}e^{-2x}+c_{2}e^{-3x}-5/6-1/12 e^x

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y^{''}+5y^'+6y=-5-e^x

y^{^{''}} + 5 y^{^{'}} + 6 y = - 5 - e^{x}

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} - \frac{5}{6} - \frac{1}{12} e^{x}

Solution steps

y^{''} (x) + 5 y^{'} (x) + 6 y = - 5 - e^{x}

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} - \frac{5}{6} - \frac{1}{12} e^{x}

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} - \frac{5}{6} - \frac{1}{12} e^{x}

What is the solution for y^{''}+5y^'+6y=-5-e^x ?
The solution for y^{''}+5y^'+6y=-5-e^x is y=c_{1}e^{-2x}+c_{2}e^{-3x}-5/6-1/12 e^x