What is the solution for y^{''}+9y=4((u^5)/3 pi-\H(13/3)pi) ?

The solution for y^{''}+9y=4((u^5)/3 pi-\H(13/3)pi) is y=c_{1}cos(3t)+c_{2}sin(3t)+(Undefined)/9

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y^{''}+9y=4((u^5)/3 pi-\H(13/3)pi)

y^{^{''}} + 9 y = 4 (\frac{u ^{5}}{3} π - H (\frac{13}{3}) π)

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{Undefined}{9}

Solution steps

y^{''} (t) + 9 y = 4 (\frac{u ^{5}}{3} π - H (\frac{13}{3}) π)

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{Undefined}{9}

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{Undefined}{9}

What is the solution for y^{''}+9y=4((u^5)/3 pi-\H(13/3)pi) ?
The solution for y^{''}+9y=4((u^5)/3 pi-\H(13/3)pi) is y=c_{1}cos(3t)+c_{2}sin(3t)+(Undefined)/9