What is the solution for y^{''}-y^'-6y=14sin(3) ?

The solution for y^{''}-y^'-6y=14sin(3) is y=c_{1}e^{3t}+c_{2}e^{-2t}-(7sin(3))/3

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y^{''}-y^'-6y=14sin(3)

y^{^{''}} - y^{^{'}} - 6 y = 14 sin (3)

y = c_{1} e^{3 t} + c_{2} e^{- 2 t} - \frac{7 sin ( 3 )}{3}

Solution steps

y^{''} (t) - y^{'} (t) - 6 y = 14 sin (3)

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- 2 t} - \frac{7 sin ( 3 )}{3}

y = c_{1} e^{3 t} + c_{2} e^{- 2 t} - \frac{7 sin ( 3 )}{3}

What is the solution for y^{''}-y^'-6y=14sin(3) ?
The solution for y^{''}-y^'-6y=14sin(3) is y=c_{1}e^{3t}+c_{2}e^{-2t}-(7sin(3))/3