What is the solution for y^{'''}+y^'=-2sin(t) ?

The solution for y^{'''}+y^'=-2sin(t) is y=c_{1}+c_{2}cos(t)+c_{3}sin(t)+tsin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{'''}+y^'=-2sin(t)

y^{^{'''}} + y^{^{'}} = - 2 sin (t)

y = c_{1} + c_{2} cos (t) + c_{3} sin (t) + t sin (t)

Solution steps

y^{'''} (t) + y^{'} (t) = - 2 sin (t)

Solve linear ODE:

y = c_{1} + c_{2} cos (t) + c_{3} sin (t) + t sin (t)

y = c_{1} + c_{2} cos (t) + c_{3} sin (t) + t sin (t)

What is the solution for y^{'''}+y^'=-2sin(t) ?
The solution for y^{'''}+y^'=-2sin(t) is y=c_{1}+c_{2}cos(t)+c_{3}sin(t)+tsin(t)