What is the solution for y^{''}+y=x^2+x-1 ?

The solution for y^{''}+y=x^2+x-1 is y=c_{1}cos(x)+c_{2}sin(x)+x^2+x-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+y=x^2+x-1

y^{^{''}} + y = x^{2} + x - 1

y = c_{1} cos (x) + c_{2} sin (x) + x^{2} + x - 3

Solution steps

y^{''} (x) + y = x^{2} + x - 1

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + x^{2} + x - 3

y = c_{1} cos (x) + c_{2} sin (x) + x^{2} + x - 3

What is the solution for y^{''}+y=x^2+x-1 ?
The solution for y^{''}+y=x^2+x-1 is y=c_{1}cos(x)+c_{2}sin(x)+x^2+x-3