What is the solution for y^{'''}-3y^{''}+2y^'=x ?

The solution for y^{'''}-3y^{''}+2y^'=x is y=c_{1}+c_{2}e^x+c_{3}e^{2x}+(x^2)/4+(3x)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{'''}-3y^{''}+2y^'=x

y^{^{'''}} - 3 y^{^{''}} + 2 y^{^{'}} = x

y = c_{1} + c_{2} e^{x} + c_{3} e^{2 x} + \frac{x ^{2}}{4} + \frac{3 x}{4}

Solution steps

y^{'''} (x) - 3 y^{''} (x) + 2 y^{'} (x) = x

Solve linear ODE:

y = c_{1} + c_{2} e^{x} + c_{3} e^{2 x} + \frac{x ^{2}}{4} + \frac{3 x}{4}

y = c_{1} + c_{2} e^{x} + c_{3} e^{2 x} + \frac{x ^{2}}{4} + \frac{3 x}{4}

What is the solution for y^{'''}-3y^{''}+2y^'=x ?
The solution for y^{'''}-3y^{''}+2y^'=x is y=c_{1}+c_{2}e^x+c_{3}e^{2x}+(x^2)/4+(3x)/4