What is the solution for y^{''}-14y^'+49y=49x+4 ?

The solution for y^{''}-14y^'+49y=49x+4 is y=c_{1}e^{7x}+c_{2}xe^{7x}+x+18/49

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y^{''}-14y^'+49y=49x+4

y^{^{''}} - 14 y^{^{'}} + 49 y = 49 x + 4

y = c_{1} e^{7 x} + c_{2} x e^{7 x} + x + \frac{18}{49}

Solution steps

y^{''} (x) - 14 y^{'} (x) + 49 y = 49 x + 4

Solve linear ODE:

y = c_{1} e^{7 x} + c_{2} x e^{7 x} + x + \frac{18}{49}

y = c_{1} e^{7 x} + c_{2} x e^{7 x} + x + \frac{18}{49}

What is the solution for y^{''}-14y^'+49y=49x+4 ?
The solution for y^{''}-14y^'+49y=49x+4 is y=c_{1}e^{7x}+c_{2}xe^{7x}+x+18/49