What is the solution for 2y^{''}+6y^'+1=95 ?

The solution for 2y^{''}+6y^'+1=95 is y=c_{1}+c_{2}e^{-3t}+(47t)/3

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2y^{''}+6y^'+1=95

2 y^{^{''}} + 6 y^{^{'}} + 1 = 95

y = c_{1} + c_{2} e^{- 3 t} + \frac{47 t}{3}

Solution steps

2 y^{''} (t) + 6 y^{'} (t) + 1 = 95

Solve linear ODE:

y = c_{1} + c_{2} e^{- 3 t} + \frac{47 t}{3}

y = c_{1} + c_{2} e^{- 3 t} + \frac{47 t}{3}

What is the solution for 2y^{''}+6y^'+1=95 ?
The solution for 2y^{''}+6y^'+1=95 is y=c_{1}+c_{2}e^{-3t}+(47t)/3