What is u^{''}+3u^'+5\H(t)=e^{-5t} ?

The answer to u^{''}+3u^'+5\H(t)=e^{-5t} is 0+3*0+5\H(t(x))=e^{-5t(x)}

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u^{''}+3u^'+5\H(t)=e^{-5t}

u^{''} + 3 u^{'} + 5 H (t (x)) = e^{- 5 t (x)}

0 + 3 \cdot 0 + 5 H (t (x)) = e^{- 5 t (x)}

Solution steps

u^{''} + 3 u^{'} + 5 H (t (x)) = e^{- 5 t (x)}

u^{''} = 0

0 + 3 u^{^{'}} + 5 H (t (x)) = e^{- 5 t (x)}

u^{'} = 0

0 + 3 \cdot 0 + 5 H (t (x)) = e^{- 5 t (x)}

What is u^{''}+3u^'+5\H(t)=e^{-5t} ?
The answer to u^{''}+3u^'+5\H(t)=e^{-5t} is 0+3*0+5\H(t(x))=e^{-5t(x)}