What is the solution for y^{''}+y^'= 1/(x^2) ?

The solution for y^{''}+y^'= 1/(x^2) is y=c_{1}+c_{2}e^{-x}-e^{-x}\Ei(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+y^'= 1/(x^2)

y^{^{''}} + y^{^{'}} = \frac{1}{x ^{2}}

y = c_{1} + c_{2} e^{- x} - e^{- x} Ei (x)

Solution steps

y^{''} (x) + y^{'} (x) = \frac{1}{x ^{2}}

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} - e^{- x} Ei (x)

y = c_{1} + c_{2} e^{- x} - e^{- x} Ei (x)

What is the solution for y^{''}+y^'= 1/(x^2) ?
The solution for y^{''}+y^'= 1/(x^2) is y=c_{1}+c_{2}e^{-x}-e^{-x}\Ei(x)