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Beliebt Rechnen >

y^{''}+2y^'+10y=25^2+3

Lösung

y^{^{''}} + 2 y^{^{'}} + 10 y = 2 5^{2} + 3

Lösung

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + \frac{314}{5}

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 10 y = 2 5^{2} + 3

Solve linear ODE:

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + \frac{314}{5}

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + \frac{314}{5}

Graph

Beliebte Beispiele

y^{''}-2y^'+2y=4x+5,y(0)=3,y^'(0)=0

y^{''}+1y=(sec(x))tan(x)

y^{''}-y^'-2y=13x+9

x^{''}+7x^'+6x=sin(2t)

y^{''}+2y=cos(8t)