What is the solution for 4y^{''}+7y^'-y=15 ?

The solution for 4y^{''}+7y^'-y=15 is y=c_{1}e^{((-7+sqrt(65))t)/8}+c_{2}e^{((-7-sqrt(65))t)/8}-15

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4y^{''}+7y^'-y=15

4 y^{^{''}} + 7 y^{^{'}} - y = 15

y = c_{1} e^{\frac{( - 7 + 65 ) t}{8}} + c_{2} e^{\frac{( - 7 - 65 ) t}{8}} - 15

Solution steps

4 y^{''} (t) + 7 y^{'} (t) - y = 15

Solve linear ODE:

y = c_{1} e^{\frac{( - 7 + 65 ) t}{8}} + c_{2} e^{\frac{( - 7 - 65 ) t}{8}} - 15

y = c_{1} e^{\frac{( - 7 + 65 ) t}{8}} + c_{2} e^{\frac{( - 7 - 65 ) t}{8}} - 15

What is the solution for 4y^{''}+7y^'-y=15 ?
The solution for 4y^{''}+7y^'-y=15 is y=c_{1}e^{((-7+sqrt(65))t)/8}+c_{2}e^{((-7-sqrt(65))t)/8}-15