What is the solution for y^{''}+y^'=3,x^2y(0)=0,y^'(0)=1 ?

The solution for y^{''}+y^'=3,x^2y(0)=0,y^'(0)=1 is y=c_{1}+c_{2}e^{-x}+3x

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y^{''}+y^'=3,x^2y(0)=0,y^'(0)=1

y^{^{''}} + y^{^{'}} = 3, x^{2} y (0) = 0, y^{^{'}} (0) = 1

y = c_{1} + c_{2} e^{- x} + 3 x

Solution steps

y^{''} (x) + y^{'} (x) = 3

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} + 3 x

y = c_{1} + c_{2} e^{- x} + 3 x

What is the solution for y^{''}+y^'=3,x^2y(0)=0,y^'(0)=1 ?
The solution for y^{''}+y^'=3,x^2y(0)=0,y^'(0)=1 is y=c_{1}+c_{2}e^{-x}+3x