What is the solution for y^{''}-2y^'-3y=e^{2t} ?

The solution for y^{''}-2y^'-3y=e^{2t} is y=c_{1}e^{3t}+c_{2}e^{-t}-1/3 e^{2t}

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y^{''}-2y^'-3y=e^{2t}

y^{^{''}} - 2 y^{^{'}} - 3 y = e^{2 t}

y = c_{1} e^{3 t} + c_{2} e^{- t} - \frac{1}{3} e^{2 t}

Solution steps

y^{''} (t) - 2 y^{'} (t) - 3 y = e^{2 t}

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- t} - \frac{1}{3} e^{2 t}

y = c_{1} e^{3 t} + c_{2} e^{- t} - \frac{1}{3} e^{2 t}

What is the solution for y^{''}-2y^'-3y=e^{2t} ?
The solution for y^{''}-2y^'-3y=e^{2t} is y=c_{1}e^{3t}+c_{2}e^{-t}-1/3 e^{2t}