What is the solution for 2y^{''}-3y^'=9x^2+10 ?

The solution for 2y^{''}-3y^'=9x^2+10 is y=c_{1}e^{(3x)/2}+c_{2}-x^3-2x^2-6x

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2y^{''}-3y^'=9x^2+10

2 y^{^{''}} - 3 y^{^{'}} = 9 x^{2} + 10

y = c_{1} e^{\frac{3 x}{2}} + c_{2} - x^{3} - 2 x^{2} - 6 x

Solution steps

2 y^{''} (x) - 3 y^{'} (x) = 9 x^{2} + 10

Solve linear ODE:

y = c_{1} e^{\frac{3 x}{2}} + c_{2} - x^{3} - 2 x^{2} - 6 x

y = c_{1} e^{\frac{3 x}{2}} + c_{2} - x^{3} - 2 x^{2} - 6 x

What is the solution for 2y^{''}-3y^'=9x^2+10 ?
The solution for 2y^{''}-3y^'=9x^2+10 is y=c_{1}e^{(3x)/2}+c_{2}-x^3-2x^2-6x