What are the solutions to the equation d(x)=12x^2-10x ?

The solutions to the equation d(x)=12x^2-10x are x=0,x=(d+10)/(12)

Find the zeros of d(x)=12x^2-10x

The zeros of d(x)=12x^2-10x are x=0,x=(d+10)/(12)

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d (x) = 12 x^{2} - 10 x

x = 0, x = \frac{d + 10}{12}

Solution steps

d (x) = 12 x^{2} - 10 x

Refine

d x = 12 x^{2} - 10 x

Switch sides

12 x^{2} - 10 x = d x

Move

d x

to the left side

12 x^{2} - 10 x - d x = 0

Factor

12 x^{2} - 10 x - d x : x (12 x - d - 10)

x (12 x - d - 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 12 x - d - 10 = 0

Solve

12 x - d - 10 = 0 : x = \frac{d + 10}{12}

The solutions to the quadratic equation are:

x = 0, x = \frac{d + 10}{12}

What are the solutions to the equation d(x)=12x^2-10x ?
The solutions to the equation d(x)=12x^2-10x are x=0,x=(d+10)/(12)
Find the zeros of d(x)=12x^2-10x
The zeros of d(x)=12x^2-10x are x=0,x=(d+10)/(12)