x^{''}+x-6=0

Lösung

x^{^{''}} + x - 6 = 0

x = c_{1} cos (t) + c_{2} sin (t) + 6

Schritte zur Lösung

x^{''} (t) + x - 6 = 0

Solve linear ODE:

x = c_{1} cos (t) + c_{2} sin (t) + 6

x = c_{1} cos (t) + c_{2} sin (t) + 6

y^{^{''}} + g^{2} y = cos (2 t), y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} - 4 y^{^{'}} - 5 y = 3 e^{- 4 t}

y^{^{''}} + 4 y = 6 cos (2 t), y (0) = 2, y^{^{'}} (0) = 1

y^{^{''}} - 9 y = - 27 t + 18 t^{2}

y^{^{'''}} - 2 y^{^{''}} + 26 y^{^{'}} = 174 e^{3 x}