What is the solution for y^{''}+2y^'-y=-4 ?

The solution for y^{''}+2y^'-y=-4 is y=c_{1}e^{(-1+sqrt(2))t}+c_{2}e^{(-1-sqrt(2))t}+4

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y^{''}+2y^'-y=-4

y^{^{''}} + 2 y^{^{'}} - y = - 4

y = c_{1} e^{(- 1 + 2) t} + c_{2} e^{(- 1 - 2) t} + 4

Solution steps

y^{''} (t) + 2 y^{'} (t) - y = - 4

Solve linear ODE:

y = c_{1} e^{(- 1 + 2) t} + c_{2} e^{(- 1 - 2) t} + 4

y = c_{1} e^{(- 1 + 2) t} + c_{2} e^{(- 1 - 2) t} + 4

What is the solution for y^{''}+2y^'-y=-4 ?
The solution for y^{''}+2y^'-y=-4 is y=c_{1}e^{(-1+sqrt(2))t}+c_{2}e^{(-1-sqrt(2))t}+4