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Beliebt Rechnen >

0.5y^{''}+6y^'+50y=240cos(10t)

Lösung

0.5 y^{^{''}} + 6 y^{^{'}} + 50 y = 240 cos (10 t)

Lösung

y = e^{- 6 t} (c_{1} cos (8 t) + c_{2} sin (8 t)) + 4 sin (10 t)

Schritte zur Lösung

0.5 y^{''} (t) + 6 y^{'} (t) + 50 y = 240 cos (10 t)

Solve linear ODE:

y = e^{- 6 t} (c_{1} cos (8 t) + c_{2} sin (8 t)) + 4 sin (10 t)

y = e^{- 6 t} (c_{1} cos (8 t) + c_{2} sin (8 t)) + 4 sin (10 t)

Graph

Beliebte Beispiele

y^{''}+y=4*cos(x)

y^{^{''}} + y = 4 \cdot cos (x)

y^{''''}-y=8t+cos(t)

y^{^{''''}} - y = 8 t + cos (t)

y^{''}+2y^'=x^2

y^{^{''}} + 2 y^{^{'}} = x^{2}

y^{''}-4y^'+5y=e^{-3t},y(0)=1,y^'(0)=0

y^{^{''}} - 4 y^{^{'}} + 5 y = e^{- 3 t}, y (0) = 1, y^{^{'}} (0) = 0

(d^2y)/(dx^2)+100y=csc(10x)

\frac{d ^{2} y}{d x ^{2}} + 100 y = csc (10 x)