What is the solution for y^{'''}+3y^{''}-4=0 ?

The solution for y^{'''}+3y^{''}-4=0 is y=c_{1}e^{-3t}+c_{2}+c_{3}t+(2t^2)/3

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y^{'''}+3y^{''}-4=0

y^{^{'''}} + 3 y^{^{''}} - 4 = 0

y = c_{1} e^{- 3 t} + c_{2} + c_{3} t + \frac{2 t ^{2}}{3}

Solution steps

y^{'''} (t) + 3 y^{''} (t) - 4 = 0

Solve linear ODE:

y = c_{1} e^{- 3 t} + c_{2} + c_{3} t + \frac{2 t ^{2}}{3}

y = c_{1} e^{- 3 t} + c_{2} + c_{3} t + \frac{2 t ^{2}}{3}

What is the solution for y^{'''}+3y^{''}-4=0 ?
The solution for y^{'''}+3y^{''}-4=0 is y=c_{1}e^{-3t}+c_{2}+c_{3}t+(2t^2)/3