What is the solution for y^{''}+y=1,6cos(t)y(0)=0,y^'(0)=0 ?

The solution for y^{''}+y=1,6cos(t)y(0)=0,y^'(0)=0 is y=c_{1}cos(t)+c_{2}sin(t)+1

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y^{''}+y=1,6cos(t)y(0)=0,y^'(0)=0

y^{^{''}} + y = 1, 6 cos (t) y (0) = 0, y^{^{'}} (0) = 0

y = c_{1} cos (t) + c_{2} sin (t) + 1

Solution steps

y^{''} (t) + y = 1

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t) + 1

y = c_{1} cos (t) + c_{2} sin (t) + 1

What is the solution for y^{''}+y=1,6cos(t)y(0)=0,y^'(0)=0 ?
The solution for y^{''}+y=1,6cos(t)y(0)=0,y^'(0)=0 is y=c_{1}cos(t)+c_{2}sin(t)+1