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Beliebt Rechnen >

y^{''}+4y^'=cos(x)

Lösung

y^{^{''}} + 4 y^{^{'}} = cos (x)

Lösung

y = c_{1} + c_{2} e^{- 4 x} + \frac{4}{17} sin (x) - \frac{1}{17} cos (x)

Schritte zur Lösung

y^{''} (x) + 4 y^{'} (x) = cos (x)

Solve linear ODE:

y = c_{1} + c_{2} e^{- 4 x} + \frac{4}{17} sin (x) - \frac{1}{17} cos (x)

y = c_{1} + c_{2} e^{- 4 x} + \frac{4}{17} sin (x) - \frac{1}{17} cos (x)

Graph

Beliebte Beispiele

y^{''}+7y^'+10y=-10+e^{4t}

y^{^{''}} + 7 y^{^{'}} + 10 y = - 10 + e^{4 t}

y^{''}+2y^'+2y=(e^{(-x)})*cos(x)

y^{^{''}} + 2 y^{^{'}} + 2 y = (e^{(- x)}) \cdot cos (x)

y^{''}-3y^'-4y=xe^x+2cos(x)-sin(x)

y^{^{''}} - 3 y^{^{'}} - 4 y = x e^{x} + 2 cos (x) - sin (x)

D(D-1)^3y=(x^2+2x)e^x

D (D - 1)^{3} y = (x^{2} + 2 x) e^{x}

y^{''}+4y=(cos(2x))/2

y^{^{''}} + 4 y = \frac{cos ( 2 x )}{2}