d(x)= 3/(2x)

解答

d (x) = \frac{3}{2 x}

x = \frac{3}{2 d}, x = - \frac{3}{2 d}; d \neq = 0

求解步骤

d (x) = \frac{3}{2 x}

在两边乘以

x

d x^{2} = \frac{3}{2}

解

d x^{2} = \frac{3}{2} : x = \frac{3}{2 d}, x = - \frac{3}{2 d}; d \neq = 0

x = \frac{3}{2 d}, x = - \frac{3}{2 d}; d \neq = 0

(d^{2} + 6 d + 9) y = \frac{e ^{- 3} x}{x ^{3}}

y^{^{''}} - 2 y^{^{'}} + y = \frac{e ^{- x}}{x}

y^{^{''}} - 12 y^{^{'}} + 36 y = 7 e^{6 x}

y^{^{''}} + \frac{1}{8} y^{^{'}} + y = 3 cos (t)

y^{^{''}} + 9 y^{^{'}} + 14 y = \frac{1}{2} sin (t)