What is the solution for y^{''}+2y^'=8x^3 ?

The solution for y^{''}+2y^'=8x^3 is y=c_{1}+c_{2}e^{-2x}+x^4-2x^3+3x^2-3x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+2y^'=8x^3

y^{^{''}} + 2 y^{^{'}} = 8 x^{3}

y = c_{1} + c_{2} e^{- 2 x} + x^{4} - 2 x^{3} + 3 x^{2} - 3 x

Solution steps

y^{''} (x) + 2 y^{'} (x) = 8 x^{3}

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 x} + x^{4} - 2 x^{3} + 3 x^{2} - 3 x

y = c_{1} + c_{2} e^{- 2 x} + x^{4} - 2 x^{3} + 3 x^{2} - 3 x

What is the solution for y^{''}+2y^'=8x^3 ?
The solution for y^{''}+2y^'=8x^3 is y=c_{1}+c_{2}e^{-2x}+x^4-2x^3+3x^2-3x