What is the solution for y^{''}+9y=10e^-1,y(0)=0,y^'(0)=0 ?

The solution for y^{''}+9y=10e^-1,y(0)=0,y^'(0)=0 is y=c_{1}cos(3t)+(10e^-)/9

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y^{''}+9y=10e^-1,y(0)=0,y^'(0)=0

y^{^{''}} + 9 y = 10 e^{-} 1, y (0) = 0, y^{^{'}} (0) = 0

y = c_{1} cos (3 t) + \frac{10 e ^{-}}{9}

Solution steps

y^{''} (t) + 9 y = 10 e^{-} 1

Solve linear ODE:

y = c_{1} cos (3 t) + \frac{10 e ^{-}}{9}

y = c_{1} cos (3 t) + \frac{10 e ^{-}}{9}

What is the solution for y^{''}+9y=10e^-1,y(0)=0,y^'(0)=0 ?
The solution for y^{''}+9y=10e^-1,y(0)=0,y^'(0)=0 is y=c_{1}cos(3t)+(10e^-)/9