Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}-32y=16cos(x)y^{''}-4y=(2x+3)e^{2x}1/4 y^{''}+4y=tan(4t)-1/4 e^ty^{''}+k^2y=sin(kx)(D^2-1)y=xe^{3x}
Frequently Asked Questions (FAQ)
What is the solution for y^{''}-4y^'+3y=1 ?
The solution for y^{''}-4y^'+3y=1 is y=c_{1}e^{3t}+c_{2}e^t+1/3