What is the answer to solvefor d,d(t)=5t^2+10-12 ?

The answer to solvefor d,d(t)=5t^2+10-12 is d=(5t^2-2)/t ;\quad t\ne 0

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solvefor d,d(t)=5t^2+10-12

solve for

d, d (t) = 5 t^{2} + 10 - 12

d = \frac{5 t ^{2} - 2}{t}; t \neq = 0

Solution steps

d (t) = 5 t^{2} + 10 - 12

Add/Subtract the numbers:

10 - 12 = - 2

d t = 5 t^{2} - 2

Divide both sides by

t; t \neq = 0

d = \frac{5 t ^{2} - 2}{t}; t \neq = 0

What is the answer to solvefor d,d(t)=5t^2+10-12 ?
The answer to solvefor d,d(t)=5t^2+10-12 is d=(5t^2-2)/t ;\quad t\ne 0