What is the solution for y^{''}+3y^'-10=0,y(0)=1,y^'(0)=9 ?

The solution for y^{''}+3y^'-10=0,y(0)=1,y^'(0)=9 is y=1+17/9-17/9 e^{-3t}+(10t)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+3y^'-10=0,y(0)=1,y^'(0)=9

y^{^{''}} + 3 y^{^{'}} - 10 = 0, y (0) = 1, y^{^{'}} (0) = 9

y = 1 + \frac{17}{9} - \frac{17}{9} e^{- 3 t} + \frac{10 t}{3}

Solution steps

y^{''} (t) + 3 y^{'} (t) - 10 = 0

Solve linear ODE:

y = 1 + \frac{17}{9} - \frac{17}{9} e^{- 3 t} + \frac{10 t}{3}

y = 1 + \frac{17}{9} - \frac{17}{9} e^{- 3 t} + \frac{10 t}{3}

What is the solution for y^{''}+3y^'-10=0,y(0)=1,y^'(0)=9 ?
The solution for y^{''}+3y^'-10=0,y(0)=1,y^'(0)=9 is y=1+17/9-17/9 e^{-3t}+(10t)/3