What is the solution for 2(d^2y)/(dx^2)-5(dy)/(dx)-3=0 ?

The solution for 2(d^2y)/(dx^2)-5(dy)/(dx)-3=0 is y=c_{1}e^{(5x)/2}+c_{2}-(3x)/5

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2(d^2y)/(dx^2)-5(dy)/(dx)-3=0

2 \frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} - 3 = 0

y = c_{1} e^{\frac{5 x}{2}} + c_{2} - \frac{3 x}{5}

Solution steps

2 \frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} - 3 = 0

Solve linear ODE:

y = c_{1} e^{\frac{5 x}{2}} + c_{2} - \frac{3 x}{5}

y = c_{1} e^{\frac{5 x}{2}} + c_{2} - \frac{3 x}{5}

What is the solution for 2(d^2y)/(dx^2)-5(dy)/(dx)-3=0 ?
The solution for 2(d^2y)/(dx^2)-5(dy)/(dx)-3=0 is y=c_{1}e^{(5x)/2}+c_{2}-(3x)/5