What is the solution for y^{''}-4y=4e^x ?

The solution for y^{''}-4y=4e^x is y=c_{1}e^{2x}+c_{2}e^{-2x}-4/3 e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-4y=4e^x

y^{^{''}} - 4 y = 4 e^{x}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{4}{3} e^{x}

Solution steps

y^{''} (x) - 4 y = 4 e^{x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{4}{3} e^{x}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{4}{3} e^{x}

What is the solution for y^{''}-4y=4e^x ?
The solution for y^{''}-4y=4e^x is y=c_{1}e^{2x}+c_{2}e^{-2x}-4/3 e^x