Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}-2y^'+y=4x^2-6+x-1exy^{''}-8y^'+16y=28x+4y^{''}+4y^'+13y=cos(t)y^{''}-4y^'=te^{-2t},y(0)=0(d^2y)/(dx^2)+8(dy)/(dx)+16y=e^{4x}
Frequently Asked Questions (FAQ)
What is the solution for y^{''}-8y^'+16y=16x+8 ?
The solution for y^{''}-8y^'+16y=16x+8 is y=c_{1}e^{4x}+c_{2}xe^{4x}+x+1