What is the solution for (d^2)/(dt^2)(θ(t))+4θ(t)=cos(c^2)(2t) ?

The solution for (d^2)/(dt^2)(θ(t))+4θ(t)=cos(c^2)(2t) is θ=c_{1}cos(2t)+c_{2}sin(2t)+(tcos(c^2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(d^2)/(dt^2)(θ(t))+4θ(t)=cos(c^2)(2t)

\frac{d ^{2} θ}{d t ^{2}} + 4 θ = cos (c^{2}) (2 t)

θ = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{t cos ( c ^{2} )}{2}

Solution steps

\frac{d ^{2} θ}{d t ^{2}} + 4 θ = cos (c^{2}) (2 t)

Solve linear ODE:

θ = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{t cos ( c ^{2} )}{2}

θ = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{t cos ( c ^{2} )}{2}

What is the solution for (d^2)/(dt^2)(θ(t))+4θ(t)=cos(c^2)(2t) ?
The solution for (d^2)/(dt^2)(θ(t))+4θ(t)=cos(c^2)(2t) is θ=c_{1}cos(2t)+c_{2}sin(2t)+(tcos(c^2))/2