What is the solution for y^{''}+10y^'+41=0 ?

The solution for y^{''}+10y^'+41=0 is y=c_{1}+c_{2}e^{-10t}-(41t)/(10)

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y^{''}+10y^'+41=0

y^{^{''}} + 10 y^{^{'}} + 41 = 0

y = c_{1} + c_{2} e^{- 10 t} - \frac{41 t}{10}

Solution steps

y^{''} (t) + 10 y^{'} (t) + 41 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 10 t} - \frac{41 t}{10}

y = c_{1} + c_{2} e^{- 10 t} - \frac{41 t}{10}

What is the solution for y^{''}+10y^'+41=0 ?
The solution for y^{''}+10y^'+41=0 is y=c_{1}+c_{2}e^{-10t}-(41t)/(10)