What is the solution for y^{''}-4y^'+3y=2x ?

The solution for y^{''}-4y^'+3y=2x is y=c_{1}e^{3x}+c_{2}e^x+(2x)/3+8/9

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y^{''}-4y^'+3y=2x

y^{^{''}} - 4 y^{^{'}} + 3 y = 2 x

y = c_{1} e^{3 x} + c_{2} e^{x} + \frac{2 x}{3} + \frac{8}{9}

Solution steps

y^{''} (x) - 4 y^{'} (x) + 3 y = 2 x

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{x} + \frac{2 x}{3} + \frac{8}{9}

y = c_{1} e^{3 x} + c_{2} e^{x} + \frac{2 x}{3} + \frac{8}{9}

What is the solution for y^{''}-4y^'+3y=2x ?
The solution for y^{''}-4y^'+3y=2x is y=c_{1}e^{3x}+c_{2}e^x+(2x)/3+8/9