What is the solution for y^{''}+16y=7x,y(0)=1,y^'(0)=4 ?

The solution for y^{''}+16y=7x,y(0)=1,y^'(0)=4 is y=cos(4x)+57/64 sin(4x)+(7x)/(16)

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y^{''}+16y=7x,y(0)=1,y^'(0)=4

y^{^{''}} + 16 y = 7 x, y (0) = 1, y^{^{'}} (0) = 4

y = cos (4 x) + \frac{57}{64} sin (4 x) + \frac{7 x}{16}

Solution steps

y^{''} (x) + 16 y = 7 x

Solve linear ODE:

y = cos (4 x) + \frac{57}{64} sin (4 x) + \frac{7 x}{16}

y = cos (4 x) + \frac{57}{64} sin (4 x) + \frac{7 x}{16}

What is the solution for y^{''}+16y=7x,y(0)=1,y^'(0)=4 ?
The solution for y^{''}+16y=7x,y(0)=1,y^'(0)=4 is y=cos(4x)+57/64 sin(4x)+(7x)/(16)