What is the solution for y^{''}-3y^'+2y=11e^3x,y^1(0)=ex ?

The solution for y^{''}-3y^'+2y=11e^3x,y^1(0)=ex is y=c_{1}e^{2x}+c_{2}e^x+(11e^3x)/2+(33e^3)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-3y^'+2y=11e^3x,y^1(0)=ex

y^{^{''}} - 3 y^{^{'}} + 2 y = 11 e^{3} x, y^{1} (0) = e x

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{11 e ^{3} x}{2} + \frac{33 e ^{3}}{4}

Solution steps

y^{''} (x) - 3 y^{'} (x) + 2 y = 11 e^{3} x

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{11 e ^{3} x}{2} + \frac{33 e ^{3}}{4}

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{11 e ^{3} x}{2} + \frac{33 e ^{3}}{4}

What is the solution for y^{''}-3y^'+2y=11e^3x,y^1(0)=ex ?
The solution for y^{''}-3y^'+2y=11e^3x,y^1(0)=ex is y=c_{1}e^{2x}+c_{2}e^x+(11e^3x)/2+(33e^3)/4