Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}+y=1,y(0)=2,y^'(0)=1y^{''}-2y^'+y=t^{-4}e^ty^{''}-2y^'-3y=x-e^x(d^2y)/(dx^2)-6y=e^{3x}(x^2+2)2y^{''}+y^'+2y=1,y(0)=0,y^'(0)=0
Frequently Asked Questions (FAQ)
What is the solution for y^{''}-y=e^tcos(t),y(0)=0,y^'(0)=0 ?
The solution for y^{''}-y=e^tcos(t),y(0)=0,y^'(0)=0 is y= 1/5 e^{-t}+2/5 e^tsin(t)-1/5 e^tcos(t)