What is the solution for y^{''}-16y=6,y(0)=1 ?

The solution for y^{''}-16y=6,y(0)=1 is y=(-c_{2}+11/8)e^{4t}+c_{2}e^{-4t}-3/8

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y^{''}-16y=6,y(0)=1

y^{^{''}} - 16 y = 6, y (0) = 1

y = (- c_{2} + \frac{11}{8}) e^{4 t} + c_{2} e^{- 4 t} - \frac{3}{8}

Solution steps

y^{''} (t) - 16 y = 6

Solve linear ODE:

y = (- c_{2} + \frac{11}{8}) e^{4 t} + c_{2} e^{- 4 t} - \frac{3}{8}

y = (- c_{2} + \frac{11}{8}) e^{4 t} + c_{2} e^{- 4 t} - \frac{3}{8}

What is the solution for y^{''}-16y=6,y(0)=1 ?
The solution for y^{''}-16y=6,y(0)=1 is y=(-c_{2}+11/8)e^{4t}+c_{2}e^{-4t}-3/8