What is the solution for y^{''}-16y^'=2e^{4x} ?

The solution for y^{''}-16y^'=2e^{4x} is y=c_{1}e^{16x}+c_{2}-1/24 e^{4x}

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y^{''}-16y^'=2e^{4x}

y^{^{''}} - 16 y^{^{'}} = 2 e^{4 x}

y = c_{1} e^{16 x} + c_{2} - \frac{1}{24} e^{4 x}

Solution steps

y^{''} (x) - 16 y^{'} (x) = 2 e^{4 x}

Solve linear ODE:

y = c_{1} e^{16 x} + c_{2} - \frac{1}{24} e^{4 x}

y = c_{1} e^{16 x} + c_{2} - \frac{1}{24} e^{4 x}

What is the solution for y^{''}-16y^'=2e^{4x} ?
The solution for y^{''}-16y^'=2e^{4x} is y=c_{1}e^{16x}+c_{2}-1/24 e^{4x}