What is the solution for y^{'''}-5y^{''}+6y^'=6e^x ?

The solution for y^{'''}-5y^{''}+6y^'=6e^x is y=c_{1}+c_{2}e^{2x}+c_{3}e^{3x}+3e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{'''}-5y^{''}+6y^'=6e^x

y^{^{'''}} - 5 y^{^{''}} + 6 y^{^{'}} = 6 e^{x}

y = c_{1} + c_{2} e^{2 x} + c_{3} e^{3 x} + 3 e^{x}

Solution steps

y^{'''} (x) - 5 y^{''} (x) + 6 y^{'} (x) = 6 e^{x}

Solve linear ODE:

y = c_{1} + c_{2} e^{2 x} + c_{3} e^{3 x} + 3 e^{x}

y = c_{1} + c_{2} e^{2 x} + c_{3} e^{3 x} + 3 e^{x}

What is the solution for y^{'''}-5y^{''}+6y^'=6e^x ?
The solution for y^{'''}-5y^{''}+6y^'=6e^x is y=c_{1}+c_{2}e^{2x}+c_{3}e^{3x}+3e^x