What is the solution for y^{''}-y=2(e^xe^{-x})^{-1} ?

The solution for y^{''}-y=2(e^xe^{-x})^{-1} is y=c_{1}e^x+c_{2}e^{-x}-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-y=2(e^xe^{-x})^{-1}

y^{^{''}} - y = 2 (e^{x} e^{- x})^{- 1}

y = c_{1} e^{x} + c_{2} e^{- x} - 2

Solution steps

y^{''} (x) - y = 2 (e^{x} e^{- x})^{- 1}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} - 2

y = c_{1} e^{x} + c_{2} e^{- x} - 2

What is the solution for y^{''}-y=2(e^xe^{-x})^{-1} ?
The solution for y^{''}-y=2(e^xe^{-x})^{-1} is y=c_{1}e^x+c_{2}e^{-x}-2